/*
Remove Linked List Elements Total Accepted: 20514 Total Submissions: 78959 My Submissions Question Solution
Remove all elements from a linked list of integers that have value val.

Example
Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
Return: 1 --> 2 --> 3 --> 4 --> 5

Credits:
Special thanks to @mithmatt for adding this problem and creating all test cases

*/

#include <iostream>
#include <vector>
#include <map>
#include <set>
#include <algorithm>
#include <string>
#include <stack>
#include <queue>
#include <fstream>
#include <sstream>
#include <unordered_set>
#include <unordered_map>
#include "print.h"
using namespace std;

/**
* Definition for binary tree*/


void testForStack()
{
	stack<int> mystack;
	mystack.push(10);
	mystack.push(20);
	mystack.top() -= 5;
	cout << "mystack.top() is now " << mystack.top() << endl;
}

void testForIntToString()
{
	int a = 10;
	stringstream ss;
	ss << a;
	string str = ss.str();
	cout << str << endl;

	string str1 = to_string(a);

}


/**
* Definition for binary tree
* struct TreeNode {
*     int val;
*     TreeNode *left;
*     TreeNode *right;
*     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
	ListNode* removeElements(ListNode* head, int val) {
		if (head == NULL)
		{
			return head;
		}

		ListNode *cur;
		cur = head;
		ListNode *pre = new ListNode(-1);
		pre->next = head;
		bool flag = true;
		while (cur!=NULL)
		{
			if (cur->val==val)
			{
				if (flag)
				{
					head = head->next;
					cur =head;
					pre->next = head;
				}
				else
				{
					flag = false;
					cur = cur->next;
					pre->next = cur;

				}
			}
			else
			{
				cur = cur->next;
				pre = pre->next;
				flag = false;
			}

		}
		return head;
	}
};
/**
* Your BSTIterator will be called like this:
* BSTIterator i = BSTIterator(root);
* while (i.hasNext()) cout << i.next();
*/

int main(int argc, char* argv[])
{

	ListNode *head = new ListNode(1);
	ListNode *head1 = new ListNode(2);
	ListNode *head2 = new ListNode(6);
	ListNode *head3 = new ListNode(3);
	ListNode *head4 = new ListNode(4);
	ListNode *head5 = new ListNode(5);

	ListNode *head6 = new ListNode(6);

	head->next = head1;
	head1->next = head2;
	head2->next = head3;
	head3->next = head4;
	head4->next = head5;
	head5->next = head6;
	int val = 6;

	Solution s;

	head = s.removeElements(head,val);

	//strRes = s.findRepeatedDnaSequences(s1);
	//cout << "The result is : " << result << endl;
	//result = s.partition(str);
	//stackTree.push(p->left);
	//stackTree.push(p->right);
	//if (s.isPalindrome(str1))
	//	cout << " True" << endl;
	//else
	//	cout << "false" << endl;
	system("pause");
	return 0;
}
//std::unordered_set<std::string> myset =
//{ "hot", "dot", "dog", "lot", "log" };

//std::cout << "myset contains:";
// for (auto it = myset.begin(); it != myset.end(); ++it)
//std::cout << " " << *it;
//;; std::cout << std::endl;

//TreeNode *root = new TreeNode(1);
//TreeNode *left = new TreeNode(2);
//TreeNode *right = new TreeNode(3);

//root->left = left;
//root->right = right;s
/*
//string s1 = "GAGAGAGAGAGA";
string s1 = "GAGAGAGAGAGA";
vector<string> strRes;

TreeNode *root = new TreeNode(1);
TreeNode *left1 = new TreeNode(2);
TreeNode *left2 = new TreeNode(5);

TreeNode *right1 = new TreeNode(3);
TreeNode *right2 = new TreeNode(4);

root->left = left1;
left1->right = left2;

root->right = right1;
right1->right = right2;

//vector<char> level1({ '1', '1', '1', '1', '0' });
//vector<char> level2({ '1', '1', '0', '1', '0' });
//vector<char> level3({ '1', '1', '0', '0', '0' });
//vector<char> level4({ '0', '0', '0', '0', '0' });


vector<vector<char>> grid;
grid.push_back(level1);
grid.push_back(level2);
grid.push_back(level3);
grid.push_back(level4);ss
*/
